The National Testing Agency (NTA) will close the objection window for the Joint CSIR-UGC NET 2024 provisional answer key today, August 11, at 11:50 PM. Candidates who appeared for the exam can check and download their answer key, response sheet, and question paper from the official website: csirnet.nta.ac.in. Candidates can challenge the provisional answer key by paying a non-refundable fee of Rs 200 for each question.
How to Raise an Objection to the CSIR UGC NET 2024 Answer Key:
- Visit the Official Website: Go to csirnet.nta.ac.in.
- Find the Answer Key Challenge Link: Look for the “Joint CSIR-UGC NET July 2024 Answer Key Challenge” link on the homepage and click on it.
- Log In: Enter your login credentials such as your application number and date of birth.
- View the Answer Key: Access the answer key and response sheet.
- Submit a Challenge: Click on the challenge answer key link to submit your objections.
- Select Questions: Choose the specific question(s) you wish to challenge.
- Upload Documents and Pay Fees: Upload any supporting documents and pay the fees. Submit your challenge.
- Save the Acknowledgment Form: Download and save the acknowledgment form for future reference.
Key Points:
- Fee for Challenge: Rs 200 per question.
- Process After Objections: The NTA will review all submitted challenges and make necessary changes to the answer key. The final answer key will be used to prepare and announce the results.
- No Updates on Challenges: Candidates will not receive individual updates about the status of their objections. The decision of the exam subject experts will be final.
Exam Details:
- Exam Dates: July 25, 26, and 27, 2024
- Shifts: Two shifts each day — First shift: 9 AM to 12 Noon, Second shift: 3 PM to 6 PM
- Number of Candidates: 2,25,335 students
- Mode: Computer-Based Test (CBT)
- Purpose: Junior Research Fellowship (JRF), Lectureship (LS), Assistant Professor, and PhD programs
For more details and updates, visit the official CSIR NET website.
